SOLUTION: Solve. Check for extraneous solutions. {{{6x=sqrt(24+12x)}}} A. -2/3 B. -1 C. 1 and -2/3 D. 1

Algebra ->  Radicals -> SOLUTION: Solve. Check for extraneous solutions. {{{6x=sqrt(24+12x)}}} A. -2/3 B. -1 C. 1 and -2/3 D. 1      Log On


   

Question 764051: Solve. Check for extraneous solutions.
6x=sqrt%2824%2B12x%29
A. -2/3
B. -1
C. 1 and -2/3
D. 1
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Your question equation was adjusted according to ability to match at least one of your choices.
Squaring both sides and dividing by 12, you get: 3x%5E2=2%2Bx,
3x%5E2-x-2=0
using general solution to quadratic formula,
x=%281%2B-+sqrt%281-4%2A3%2A%28-2%29%29%29%2F6
x=-2%2F3 or x=1



---------------------------------
Your originally given equation would properly be written in text and tags, this way:
6x=sqrt(24+12x)
and then using triple closing brackets on the right side and triple opening brackets on the left side,
6x=sqrt%2824%2B12x%29