SOLUTION: i dont understand what they are asking. here's the question : using the discriminant tell whether the equation has two solutions,one solution,or no real solution. problem: x^2-5x+6
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Question 733581: i dont understand what they are asking. here's the question : using the discriminant tell whether the equation has two solutions,one solution,or no real solution. problem: x^2-5x+6=0......how do i solve this equation? Answer by sachi(548) (Show Source):
You can put this solution on YOUR website! in an eqn ax^2+bx+c=0 the discriminant=b^2-4ac
& the solns are [-b+-sqrt(b^2-4ac)]/2a
now if 1)b^2=4ac then there is one solution i.e -b/2a
if 2)b^2>4ac then there are two solutions i.e [-b+-sqrt(b^2-4ac)]/2a
but if 3)b^2<4ac then there are no real solutions asthe sqrt will have no real value
now here in x^2-5x+6=0 a=1,b=-5& c=6
so b^2-4ac =1
so there are two solutions by 2) above 3 & 2 ans
