SOLUTION: Hey, I need some help solving this problem, please help! 3[(x+3)^(3/4)]=81 I don't know if the 3 in the 3[(x+3)^(3/4)] goes into the root. So does it end up to look like this->

Algebra ->  Radicals -> SOLUTION: Hey, I need some help solving this problem, please help! 3[(x+3)^(3/4)]=81 I don't know if the 3 in the 3[(x+3)^(3/4)] goes into the root. So does it end up to look like this->       Log On


   



Question 722831: Hey, I need some help solving this problem, please help!
3[(x+3)^(3/4)]=81
I don't know if the 3 in the 3[(x+3)^(3/4)] goes into the root. So does it end up to look like this-> 3 multiplied by the 4th root of (x+3)^3 or 3(x+3)^3 all inside the 4th root?
Thanks so much, I do need a reply in the next 15 or less minutes so please and thank you. Could you make sure you tell me all the steps on how to solve this problem. I need to make sure I'm going threw the whole thing correctly.
Thanks again,
Kylee Hill

Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
3%5B%28x%2B3%29%5E%283%2F4%29%5D=81.... Those grouping symbols do not carry into rendering. The given equation is the same as 3((x+3)^(3/4))=81, which is renderable as 3%28%28x%2B3%29%5E%283%2F4%29%29=81

The 3 is a factor. The square brackets are grouping symbols. Divide both sides of the equation by 3.

Continue with %28x%2B3%29%5E%283%2F4%29=27