SOLUTION: I need help with this three problems i've tried them every way possible but i don't get the answer. I have the answers but i don't know how to get to them.
so i can understand the
Algebra ->
Radicals
-> SOLUTION: I need help with this three problems i've tried them every way possible but i don't get the answer. I have the answers but i don't know how to get to them.
so i can understand the
Log On
Question 70971: I need help with this three problems i've tried them every way possible but i don't get the answer. I have the answers but i don't know how to get to them.
so i can understand them and do my own homework. please help.
Problem# 30 for chapter 9.5
Solve each of the equaitons . Be sute to show how to check the solutions.
inside of the square root it has : 2y+7 then space +4 = y
Problem # 16 from chapter 9.6
Geometry. For the home described in exercise 15, if the roof is 7m from peak to eave and the attic space is 3m high at the peak, how long does each of the pieces of insultaion need to be? round to the nearest tenth.
You can put this solution on YOUR website! #30. Solve: Subtract 4 from both sides of the equation. Now square both sides. Simplify the right side. Subtract (2y+7) from both sides. Factor the quadratic equation. Apply the zero product principle. and/or and
Check:
y = 1 Note that or +3 The extraneous root of (+3) was introduced when squaring
y= 9 Note that or -5 The extaneous root of (-5) was introduced when squaring
#16
The geometry of the problem describes a right triangle in which the height is 3 m. and the length of the hypotenuse is 7 m.
Use the Pythagorean theorem to calculate the third side of this triangle. The hypotenuse is 7 m. so c = 7 and the height is 3 m. so a = 3 Solve for b which is the required length of the insulation. Subtract 9 from both sides. Take the square root of both sides. To the nearest tenth.