You can put this solution on YOUR website! which quadratic equation has the roots 2-radical 3 and 2 + radical 3?
**
[x-(2-√3)][(x-(2+√3)]=0
FOIL
x^2-(2-√3)x-(2+√3)x+(2-√3)(2+√3)
x^2+(-2+√3-2-√3)x+(4-3)
x^2-4x+1=0
Check with quadratic formula:
a=1, b=-4, c=1
x=[-b±√(b^2-4ac)]/2a
x=[4±√(16-4*1*1)]/2*1
x=[4±√(12)]/2
x=[4±2√(3)]/2
x=2±√3