SOLUTION: I have been working on this problem for hours now. I know what the answer is but whenever i do the problem it does not come out to be right! Here is the problem: The radius of

Algebra ->  Radicals -> SOLUTION: I have been working on this problem for hours now. I know what the answer is but whenever i do the problem it does not come out to be right! Here is the problem: The radius of      Log On


   

Question 703188: I have been working on this problem for hours now. I know what the answer is but whenever i do the problem it does not come out to be right! Here is the problem:
The radius of the surface of a circle pool is (2+sqrt(xy^5))meter. Express the area of the pool in simplest form.
The answer is supposed to be:
Pi (4+xy^5 +4y^2 sqrt(xy)) m^2
I just dont understand the steps to take to get there
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
You say the radius is "(2+sqrt(xy^5))meter". That is %282%2Bsqrt%28xy%5E5%29%29meter.
area+=+pi%2Ar%5E2
area=pi%2A%282%2Bsqrt%28xy%5E5%29%29%5E2
=pi%2A%282%5E2%2B4%2Asqrt%28xy%5E5%29%2Bx%2Ay%5E5%29
=pi%2A%284%2B4%2Ay%5E2%2Asqrt%28xy%29%2Bx%2Ay%5E5%29

In case of confusion in the final step, for the middle term,
know that sqrt%28N%5E2%29=N. Every TWO occurences of the same factor under the square root radical can be taken outside as a single occurence.
4%2Asqrt%28x%2AY%5E5%29=4%2Asqrt%28x%2Ay%5E2%2Ay%5E2%2Ay%29
=4%2Ay%2Ay%2Asqrt%28x%2Ay%29
=4%2Ay%5E2%2Asqrt%28x%2Ay%29