SOLUTION: please hlep me solve this equation {{{6x^2+13x-15=0}}}

Algebra ->  Radicals -> SOLUTION: please hlep me solve this equation {{{6x^2+13x-15=0}}}       Log On


   

Question 68550: please hlep me solve this equation 6x%5E2%2B13x-15=0

Found 2 solutions by rmromero, Earlsdon:
Answer by rmromero(383) About Me  (Show Source):
You can put this solution on YOUR website!
1 Factor 6x%5E2%2B13x-15=0


(6x - 5) (x + 3) = 0
2. Set each factor to zero


6x - 5 = 0, x + 3 = 0
3. Solve for x.
6x - 5 = 0
highlight+%28x+=+5%2F6%29

x + 3 = 0
highlight+%28x+=-3%29
Checking:
6x%5E2%2B13x-15=0, +x+=+5%2F6

6%285%2F6%29%5E2%2B13%285%2F6%29-15=0

%2825%2F6%29+%2B+%2865%2F6%29+-+15+=+0
25 + 65 - 90 = 0
90 - 90 = 0
0 = 0 ------------>> True


6x%5E2%2B13x-15=0, x+=+-3

6%28-3%29%5E2%2B13%28-3%29-15=0
54 - 39 - 15 = 0
54 - 54 = 0
0 = 0 ----------->> True

There the solution of the equation is {5/6, -3} or x = 5/6 and x = -3

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve:
6x%5E2%2B13x-15+=+0 Factor.
%286x-5%29%28x%2B3%29+=+0 Apply the zero product principle.
6x-5+=+0 and/or x%2B3+=+0
If 6x-5+=+0 then 6x+=+5 so x+=+5%2F6
If x%2B3+=+0 then x+=+-3
Solutions:
x+=+5%2F6
x+=+-3