SOLUTION: y+1= square root of 5y-1

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Question 678974: y+1= square root of 5y-1
Answer by ReadingBoosters(3246) About Me  (Show Source):
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y%2B1+=+sqrt%285y-1%29
...
%28y%2B1%29%5E2+=+sqrt%285y-1%29%5E2
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y%5E2%2B2y+%2B+1+=+5y+-+1
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y%5E2+%2B+2y+-+5y+%2B+1+%2B+1+=+0
...
y%5E2+-+3y+%2B+2+=+0
...
(y-2)(y-1) = 0
y-1=0, so y = 1
y-2=0, so y = 2
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