SOLUTION: how do i solve sqrt(2x) + 2 > 4
-2 -2
I then got sqrt(2x) > 2
then squared both sides 2x > 4
x > 2
then i did 2x >=
Algebra ->
Radicals
-> SOLUTION: how do i solve sqrt(2x) + 2 > 4
-2 -2
I then got sqrt(2x) > 2
then squared both sides 2x > 4
x > 2
then i did 2x >=
Log On
Question 671032: how do i solve sqrt(2x) + 2 > 4
-2 -2
I then got sqrt(2x) > 2
then squared both sides 2x > 4
x > 2
then i did 2x >= 0
x >= 0
0 <= x > 2 is this right? or where did I go wrong.
Thanks in Advance
You can put this solution on YOUR website! Most importantly,
x cannont be >=0 to achieve greater than 4
...
0 + 2 = 2 which is not > 4
...
The first answer takes care of the second.
x cannot be greater than 2 yet equal to or greater than zero.
...
The first answer exludes 1, while the second answer includes it.
...
You first answer was enough to solve the inequality
x > 2
...
So long as x is > 2, it will always be > 0
.....................
Delighted to help.
-Reading Boosters
Wanting for others what we want for ourselves.
www.MyHomeworkAnswers.com
You can put this solution on YOUR website!
how do i solve sqrt(2x) + 2 > 4
-2 -2
I then got sqrt(2x) > 2
then squared both sides 2x > 4
x > 2
then i did 2x >= 0
x >= 0
0 <= x > 2 is this right? or where did I go wrong.
Thanks in Advance
That's it, and it only!!! You then do the check to make sure that your answer is correct.
Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
(