SOLUTION: find a quadratic equation having the given roots.
{1/4-sqrt(-5)/4, 1/4+ sqrt(-5)/4}
the 4 is not under the radical sign.
in the book it shows 1+i sqrt5 and 1-i sqrt5 all div
Algebra ->
Radicals
-> SOLUTION: find a quadratic equation having the given roots.
{1/4-sqrt(-5)/4, 1/4+ sqrt(-5)/4}
the 4 is not under the radical sign.
in the book it shows 1+i sqrt5 and 1-i sqrt5 all div
Log On
Question 663668: find a quadratic equation having the given roots.
{1/4-sqrt(-5)/4, 1/4+ sqrt(-5)/4}
the 4 is not under the radical sign.
in the book it shows 1+i sqrt5 and 1-i sqrt5 all divided by 4
I had an answer on another site of:
-a = Sum of roots
b = Product of roots.
So in this case,
a = -1/4
b = 6/4 = 3/2
Therefore the equation is x2 - x/4 + 3/2 = 0
But when I put this in a quadric equation solver it is not correct. I get a=-1/2 but that doesn't work either.
Thank you!
(