SOLUTION: Hello I'm having trouble solving a equation containing two radicals. I keep getting the wrong answer even though I isolate one radical, square it, isolate the second, and square th
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-> SOLUTION: Hello I'm having trouble solving a equation containing two radicals. I keep getting the wrong answer even though I isolate one radical, square it, isolate the second, and square th
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Question 663418: Hello I'm having trouble solving a equation containing two radicals. I keep getting the wrong answer even though I isolate one radical, square it, isolate the second, and square that.
The equation is
sqrt(5x-7) + sqrt(2x+8) +2 = 0
Thank you for the help in advance! Found 2 solutions by Alan3354, stanbon:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! sqrt(5x-7) + sqrt(2x+8) +2 = 0
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If you post your work, we can check it.
You can put this solution on YOUR website! sqrt(5x-7) + sqrt(2x+8) +2 = 0
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sqrt(5x-7) = -[sqrt(2x+8)+2)
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Square both sides:
5x-7 = 2x+8 + 4sqrt(2x+8)+4
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3x-19 = 4sqrt(2x+8)
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Square both sides:
9x^2 - 114x + 361 = 16(2x+8)
9x^2 - 114x + 361 = 32x + 128
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9x^2 -146x + 233 = 0
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Use the Quadratic formula to get:
x = 14.428
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cheers,
Stan H.
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