SOLUTION: The domain of the function: sqrt (t-67)^(1/3)

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Question 661584: The domain of the function: sqrt (t-67)^(1/3)
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
The domain of the function:
sqrt (t-67)^(1/3)
= [(t-67)^(1/3)]^1/2
= (t-67)^(1/6)
restriction: radicans of even roots≥0
t-67≥0
t≥67
domain: [67,∞)