SOLUTION: Direction: Divide and simplify if possible. cuberoot(x^2+5x+6)/cuberoot(x+2) I did the following and got stuck: cuberoot(x^2+5x+6/x+2)=Cuberoot(5x+3) I canceled out an x fr

Algebra ->  Radicals -> SOLUTION: Direction: Divide and simplify if possible. cuberoot(x^2+5x+6)/cuberoot(x+2) I did the following and got stuck: cuberoot(x^2+5x+6/x+2)=Cuberoot(5x+3) I canceled out an x fr      Log On


   

Question 659128: Direction: Divide and simplify if possible.
cuberoot(x^2+5x+6)/cuberoot(x+2)
I did the following and got stuck: cuberoot(x^2+5x+6/x+2)=Cuberoot(5x+3)
I canceled out an x from the top and divided 6 by 2 to get the answer.
The book says I should have got cuberoot(x+3) for the answer. What is the correct way to solve this?
Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

Direction: Divide and simplify if possible.
cuberoot(x^2+5x+6)/cuberoot(x+2)
I did the following and got stuck: cuberoot(x^2+5x+6/x+2)=Cuberoot(5x+3)
I canceled out an x from the top and divided 6 by 2 to get the answer.
The book says I should have got cuberoot(x+3) for the answer. What is the correct way to solve this?

%28root%283%2C+x%5E2+%2B+5x+%2B+6%29%29%2Froot%283%2C+x+%2B+2%29 ------ root%283%2C+%28x%5E2+%2B+5x+%2B+6%29%2F%28x+%2B+2%29%29 ------- root%283%2C+%28%28x+%2B+3%29%28x+%2B+2%29%29%2F%28x+%2B+2%29%29 ------- root%283%2C+%28%28x+%2B+3%29cross%28%28x+%2B+2%29%29%29%2Fcross%28%28x+%2B+2%29%29%29 ------- highlight_green%28root%283%2C+x+%2B+3%29%29

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