SOLUTION: What are the solutions for x in the given equation? {{{6/(x-4)=(x-3)/(x+2)}}}
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Algebra: Radicals -- complicated equations involving roots
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Question 656266
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What are the solutions for x in the given equation?
Answer by
Edwin McCravy(20055)
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Cross multiply:
6(x+2) = (x-3)(x-4)
6x+12 = x²-7x+12
0 = x²-13x
0 = x(x-13)
Use the zero-factor property
x = 0; x-13 = 0
x = 13
There are two solutions, 0 and 13.
Edwin