SOLUTION: hi!! please help me i already answered it but I'm just checking if my answer is correct because I'm not sure of my answers. hope you can help me. 1) 4√10/3 a^3b^5 multip

Algebra ->  Radicals -> SOLUTION: hi!! please help me i already answered it but I'm just checking if my answer is correct because I'm not sure of my answers. hope you can help me. 1) 4√10/3 a^3b^5 multip      Log On


   

Question 651607: hi!! please help me i already answered it but I'm just checking if my answer is correct because I'm not sure of my answers. hope you can help me.
1) 4√10/3 a^3b^5 multiplied by 4√24a^2b^3 ( the 4 is suppose to be small like an exponent.)
( rationalizing denominator)
1) (√7 – 3) / (√7 + 2)
2) (2√3) / (2√3 - 3√2)
3) (2√2 - 3√7) / (3√2 +2√7)
3) (5√3 -4√5) / (2√5 +3√3)
this is in fraction form! the one that are in radical sign please dont get the radical of it if it has a decimal!!
please show the solution!1 thanks :))
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
1) 4√10/3 a^3b^5 multiplied by 4√24a^2b^3 ( the 4 is suppose to be small like an exponent.)
-----
= 4th root[(10/3 *24)a^5b^8]
---
= 4th root[80*a^5b^8]
---
= 4th root[16b^8]*4th root[5a^5]
----
= 2b*4th root[5a^5]
============================================

( rationalizing denominator)
1) (√7 – 3) / (√7 + 2)
----
= [(sqrt(7)-sqrt(3))(sqrt(7)-sqrt(2))] / [sqrt(7)+2))(sqrt(7)-sqrt(2)]
-----
= [7-sqrt(14)-sqrt(21)+sqrt(6)] / [7-2]
etc.
============================
2) (2√3) / (2√3 - 3√2)
----
[2sqrt(3)*(2sqrt(3 + 3sqrt(2))] / [(2sqrt(3)-3sqrt(2))(2sqrt(3)+3sqrt(2)]
---------
= [4*3+6sqrt(6)] / [4*3-9*2]
etc.
=============
I'll leave the others to you.
Cheers,
Stan H.

3) (2√2 - 3√7) / (3√2 +2√7)
3) (5√3 -4√5) / (2√5 +3√3)
this is in fraction form! the one that are in radical sign please dont get the radical of it if it has a decimal!!
please show the solution!