SOLUTION: I can't send square root signs so please bare with me. if you have an equation that has say, the square root of (x-3) -x=-3 I know you are supposed to square both sides but

Algebra ->  Radicals -> SOLUTION: I can't send square root signs so please bare with me. if you have an equation that has say, the square root of (x-3) -x=-3 I know you are supposed to square both sides but       Log On


   

Question 640537: I can't send square root signs so please bare with me.

if you have an equation that has say, the square root of (x-3) -x=-3
I know you are supposed to square both sides but I'm having deciding what to do with the x? Do i move it to the other side of the equation or continue to work with it on the side with the square root. Please help. My Algebra teacher never did a problem like this in class. My homework isn't due until next Thursday (August 30th) but please respond as quickly as possible. I would really like to know what I'm doing on my homework and not fall behind.
Thank you,
Chelsea
Found 2 solutions by jim_thompson5910, benni1013:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%28x-3%29+-x=-3

sqrt%28x-3%29=-3%2Bx

sqrt%28x-3%29=x-3

%28sqrt%28x-3%29%29%5E2=%28x-3%29%5E2

x-3=%28x-3%29%5E2

x-3=x%5E2+-+6x+%2B+9

0=x%5E2+-+6x+%2B+9-x%2B3

0=x%5E2+-+7x+%2B+12

x%5E2+-+7x+%2B+12+=+0

%28x-3%29%28x-4%29+=+0

x-3=0 or x-4+=+0

x=3 or x=4

So the *possible* solutions are x=3 or x=4

Make sure you check both of them (I'll let you do this) to actually confirm that they are true solutions.

Let me know if you have any questions.

Answer by benni1013(206) About Me  (Show Source):
You can put this solution on YOUR website!
It cancels. Also you can also write the equivalent of a square root by raising anything to the 1/2 power.
x-3-x=9
3=9
No solution.