Question 62579: I tried this but i think it's wrong can u please help again:
Sqrt x+9 +3=x
x+9 is in the radical(square root) Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Sqrt(x+9) +3=x
sqrt(x+9) = x-3
Square both sides to get:
x+9 = x^2-6x+9
x^2-7x=0
x(x-7)=0
x=0 or x=7
Check answer in the orignal equation:
If x=0, sqrt(0+9)=0-3
Wrong as sqrt9 = +3
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If x=7, sqrt(7+9)=7-3
sqrt16=4
4=4
Good solution
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Final solution:
x=7
Cheers,
Stan H.
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