SOLUTION: I need your help thank U: sqrt 5x-2 +8=0 5x-2 under the radical(Square root)

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Question 62570: I need your help thank U:
sqrt 5x-2 +8=0
5x-2 under the radical(Square root)
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%285x-2%29%2B8=0
sqrt%285x-2%29%2B8-8=0-8
sqrt%285x-2%29=-8
%28sqrt%285x-2%29%29%5E2=%28-8%29%5E2
5x-2=64
5x-2%2B2=64%2B2
5x=66
5x%2F5=66%2F5
x=66%2F5
Check for extraneous solutions.
sqrt%285%2866%2F5%29-2%29%2B8=0
sqrt%2866-2%29%2B8=0
sqrt%2864%29%2B8=0
8%2B8=0
16=0 x=66/5 is extraneous, this has no solution.
Happy Calculating!!!