SOLUTION: I have to solve this equation with radicals and I am not sure if i just square both sides and then that removes the radicals and it becomes a normal equation. I think that's how t

Algebra ->  Radicals -> SOLUTION: I have to solve this equation with radicals and I am not sure if i just square both sides and then that removes the radicals and it becomes a normal equation. I think that's how t      Log On


   

Question 622116: I have to solve this equation with radicals and I am not sure if i just square both sides and then that removes the radicals and it becomes a normal equation. I think that's how to do it but for some reason I think there might be a different rule for when two radicals are on two sides of the equations. If you could help me with this and show work I would really appreciate it, this has me stumped.
sqrt%285x-3%29=sqrt%289x-7%29
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
square both sides and the radicals go away. In this case, it is a simple thing to do
sqrt%285x-3%29+=+sqrt%289x-7%29 now square both sides
%28sqrt%285x-3%29%29%5E2+=+%28sqrt%289x-7%29%29%5E2
5x-3+=+9x+-7
4+=+4x
1+=+x
check your answers by solving the original equations with x = 1 to see if both sides resolve to the same value