SOLUTION: what is the solution to radical(x+10)+radical(3-x)=5 please

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Question 612920: what is the solution to radical(x+10)+radical(3-x)=5 please
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%28x%2B10%29%2Bsqrt%283-x%29=5

sqrt%28x%2B10%29=5-sqrt%283-x%29

%28sqrt%28x%2B10%29%29%5E2=5-sqrt%283-x%29

x%2B10=%285-sqrt%283-x%29%29%5E2

x%2B10=25-10%2Asqrt%283-x%29%2B3-x

x%2B10=28-10%2Asqrt%283-x%29-x

x%2B10-28%2Bx=-10%2Asqrt%283-x%29

2x-18=-10%2Asqrt%283-x%29

%282x-18%29%5E2=%28-10%2Asqrt%283-x%29%29%5E2

%282x-18%29%5E2=100%2A%283-x%29

4x%5E2-72x%2B324=100%2A%283-x%29

4x%5E2-72x%2B324=300-100x

4x%5E2-72x%2B324-300%2B100x=0

4x%5E2%2B28x%2B24=0

4%28x%5E2%2B7x%2B6%29=0

4%28x%2B6%29%28x%2B1%29=0

x%2B6=0 or x%2B1=0

x=-6 or x=-1

So the possible solutions are x=-6 or x=-1

I'll let you check your answers

Note: a check is crucial when dealing with radical equations since one of those possible solutions may not even be a solution at all.