SOLUTION: solve for x by using the quadratic formula: 9x^2-6x+5=0 thanks so much

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Question 60849: solve for x by using the quadratic formula: 9x^2-6x+5=0
thanks so much
Found 2 solutions by jai_kos, ikleyn:
Answer by jai_kos(139) About Me  (Show Source):
You can put this solution on YOUR website!
9x^2-6x+5=0
It is the quadratic equation of the form.
ax^2+bx +c =0
Comparing the equation, we get
a = 9, b = -6 and c = 5
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-%28-6%29+%2B-+sqrt%28+%28-6%29%5E2-4%2A9%2A5+%29%29%2F%282%2A9%29+
x+=+%286+%2B-+sqrt%28+36-180+%29%29%2F%2818%29+

x+=+%286+%2B-+sqrt%28144%29%29%2F%2818%29+

x+=+%286+%2B-+sqrt%28144%29%29%2F%2818%29+

Answer by ikleyn(53742) About Me  (Show Source):
You can put this solution on YOUR website!
.
solve for x by using the quadratic formula: 9x^2-6x+5=0
thanks so much
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        The solution by @jai_kos is incorrect.
        See my correct solution below.


9x^2-6x+5=0

It is the quadratic equation of the form.

ax^2+bx +c =0

Comparing the equations, we get
a = 9, b = -6 and c = 5

x = %28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

x = %28-%28-6%29+%2B-+sqrt%28+%28-6%29%5E2-4%2A9%2A5+%29%29%2F%282%2A9%29+

x = %286+%2B-+sqrt%28+36-180+%29%29%2F18+

x = %286+%2B-+sqrt%28-144%29%29%2F18+

x = %286+%2B-+12i%29%2F18+ = %281+%2B-+2i%29%2F3.

Thus the given equation has no real solutions.
It has two conjugate solutions in complex numbers.

Solved correctly.