SOLUTION: HI! I'm doing test corrections and I'm stumped on one problem. the original equation is: {{{ sqrt( 54x )/ sqrt( x^5 ) }}} I have already tried the problem a few times but m

Algebra ->  Radicals -> SOLUTION: HI! I'm doing test corrections and I'm stumped on one problem. the original equation is: {{{ sqrt( 54x )/ sqrt( x^5 ) }}} I have already tried the problem a few times but m      Log On


   

Question 604164: HI! I'm doing test corrections and I'm stumped on one problem.
the original equation is:
+sqrt%28+54x+%29%2F+sqrt%28+x%5E5+%29+
I have already tried the problem a few times but my best guess so far ended up being:
+3x%5E3sqrt%28+6+%29%2F+x%5E5+
I really hope I wrote those out wrong. It's my first time on this site. Thanks so much for your time :)
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
HI! I'm doing test corrections and I'm stumped on one problem.
the original equation is:
+sqrt%28+54x+%29%2F+sqrt%28+x%5E5+%29+
-------------
That's not an equation. I can tell, there's no equal sign.
You can simplify it. Math people are obsessed with getting radicals out of the denominator.
-----------
+sqrt%28+54x+%29%2F+sqrt%28+x%5E5+%29+
= +sqrt%28+54x%2Fx%5E5+%29+
= +sqrt%28+54%2Fx%5E4+%29+
= +sqrt%2854%29%2Fx%5E2+
That's better, right?
------
You can do more:
= +sqrt%289%2A6%29%2Fx%5E2+
= 3sqrt%286%29%2Fx%5E2+

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt( 54x )/ sqrt( x^5)
-----
= sqrt[(54x/x^5]
---
= sqrt(9*6/x^4]
---
= (3/x^2)*sqrt(6)
===================
Cheers,
Stan H.