Question 59935: 18. Solve
(rs)x-1=x-3
I have no idea on how to solve this problem and my head is beginning to hurt. Can someone help me please.
Answer by chitra(359)  (Show Source):
You can put this solution on YOUR website! The given expression is:
rs(x - 1) = x - 3
We remove the radical on the left hand side by squaring both sides of the given expression.
That is:
(x - 1) = (x - 3)^2
Expanding the right hand side by using the formula (a - b)^2, we get:
(x - 1) = x^2 - 6x + 9
Adding 1 - x to both sides of the above equation, we get:
x^2 - 6x + 9 + 1 - x = 0
x^2 - 7x + 10 = 0 [Adding the like terms, we get]
Using the method of Factorization, we get:
x^2 - 5x - 2x + 10 = 0
x(x - 5) - 2(x - 5) = 0
(x - 2)(x - 5) = 0
Thus, the values of x are 2 and 5.
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