SOLUTION: Use square root procedure to solve the following quadratic equation. I was able to get down to the last part of problem but have been stumped since. 2x^2=48 1) 2x^2/2=48/2

Algebra ->  Radicals -> SOLUTION: Use square root procedure to solve the following quadratic equation. I was able to get down to the last part of problem but have been stumped since. 2x^2=48 1) 2x^2/2=48/2       Log On


   

Question 59881This question is from textbook College Algebra
: Use square root procedure to solve the following quadratic equation. I was able to get down to the last part of problem but have been stumped since.
2x^2=48
1) 2x^2/2=48/2
2) x^2=24
3) x=+-sq root 24
4) ???? This question is from textbook College Algebra

Found 2 solutions by checkley71, funmath:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
2X^2=48
X^2=48/2
X^2=24
X=+-SQRT24
X=+-2SQRT6 OR
X=+-2*2.4494897 OR
X=+-4.8989794

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Use square root procedure to solve the following quadratic equation. I was able to get down to the last part of problem but have been stumped since.
2x^2=48
1) 2x^2/2=48/2
2) x^2=24
3) x=+-sq root 24
4) ????
I am assuming, that you need this reduced and not an approximate answer that you can get with a calculator. Separate 24 into factors in which one is a perfect square.
x=-sqrt%2824%29 and x=sqrt%2824%29
x=-sqrt%284%29%2Asqrt%286%29 and x=sqrt%284%29%2Asqrt%286%29
The square root of 4 is 2.
x=-2%2Asqrt%286%29 and x=2%2Asqrt%286%29
Happy Calculating!!!