SOLUTION: (I have used the tiny ` characters to space and preserve formatting)
```````_``````````````_
x^2 \/3 + 6x + 7 \/3
TRIED:
------
``````'`````_
(x^2+7)\/3 =-6x
3x^2+21 = -18
Algebra ->
Radicals
-> SOLUTION: (I have used the tiny ` characters to space and preserve formatting)
```````_``````````````_
x^2 \/3 + 6x + 7 \/3
TRIED:
------
``````'`````_
(x^2+7)\/3 =-6x
3x^2+21 = -18
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Question 59525: (I have used the tiny ` characters to space and preserve formatting)
```````_``````````````_
x^2 \/3 + 6x + 7 \/3
TRIED:
------
``````'`````_
(x^2+7)\/3 =-6x
3x^2+21 = -18x
3x^2+18x+21 ->> Solved by quadratic formula
Didn't work :(
I have the feeling that I need to SQUARE both sides instead of multiplying by 3, but I don't see why multiplying by 3 wouldn't work, because it does the same thing to both sides.
Any help appreciated! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! ```````_``````````````_
x^2 \/3 + 6x + 7 \/3
--------------------
x^2 sqrt3 +6x + 7 sqrt3
=(x^2+7)sqrt3 +6x
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Comment: You have not posted an equation so there
is no "solution". You can only try to "simplify"
the expression. That's what we did.
Cheers,
Stan H.