SOLUTION: solve the following radical: {{{ sqrt ( 3x )+ sqrt ( 2x-1 ) = 5 / sqrt ( 2x-1 ) }}}

Algebra ->  Radicals -> SOLUTION: solve the following radical: {{{ sqrt ( 3x )+ sqrt ( 2x-1 ) = 5 / sqrt ( 2x-1 ) }}}      Log On


   

Question 569284: solve the following radical: +sqrt+%28+3x+%29%2B+sqrt+%28+2x-1+%29+=+5+%2F+sqrt+%28+2x-1+%29+
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt ( 3x )+ sqrt ( 2x-1 ) = 5 / sqrt ( 2x-1 )
√3x+√(2x-1)=5/√(2x-1)
multiply both sides by √(2x-1)
√(6x^2-3x)+2x-1=5
√(6x^2-3x)=-2x+6
square both sides
6x^2-3x=4x^2-24x+36
2x^2+21x-36=0
(x+12)(2x-3)=0
x=-12
or
x=3/2