SOLUTION: The square root of 32x + the square root of 2x - the square root of 18x =? Please help!

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Question 54826: The square root of 32x + the square root of 2x - the square root of 18x =?
Please help!
Found 2 solutions by hulamc723, tutorcecilia:
Answer by hulamc723(15) About Me  (Show Source):
You can put this solution on YOUR website!
first factor out 32x to get 2*2*2*2*2*x now simplify to 4 the square root of 2x, then keep the 2x the same. factor out 18 to get 2*3*3*x. simplify to get 3 the square root of 2x no since the all are like terms just add 8+1-3 and then you get 6 now place the 6 in front of the square root of 2x and you get 6 the square root of 2x!

Answer by tutorcecilia(2152) About Me  (Show Source):
You can put this solution on YOUR website!
%28sqrt%2832x%29%2Bsqrt%282x%29-sqrt%2818x%29%29[Treat each radical as a term. You can add and subtract like-radicals the same as you would add and subtract like-terms]
.
%28sqrt%288%2A4x%29%2Bsqrt%282x%29-sqrt%289%2A2x%29%29 [So, try to make the radical terms match]
%284sqrt%282x%29%2Bsqrt%282x%29-3sqrt%282x%29%29 [Simplify]
%284sqrt%282x%29%2Bsqrt%282x%29-3sqrt%282x%29%29[Since the radicals are now "like-terms" (sqrt(2x)), you can add the coefficients of each radical]
.
%284sqrt%282x%29%2B1sqrt%282x%29-3sqrt%282x%29%29[Add the coefficients: 4+1-3=2]
%282sqrt%282x%29%29%29