You can put this solution on YOUR website!
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Break everything into prime factors
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Write (2)·(2) as (2)² and (x)·(x) as (x)²
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Take the (2)² out in front of the radical as just 2
Take the (x)² out in front of the radical as just |x|
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Rationalize the denominator by multiplying under the
radical by 5/5:
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OR
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Write the (5)·(5) as (5)²
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Take (5)² out in front of the radical as 5, and
since it came from the bottom, put it under the 2|x|.
The absolute value bars are necessary because the original
problem is a square root and even root radicals may never
represent a negative number, so we need absolute
values around the x in case x turned out to be
negative.
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This can be written as
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Edwin