SOLUTION: Using Radical Operations In Real Life Triangle # 1 6 inch (Left)/__\Hypotenuse=x (right side) 9 inch (bottom)

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Question 544544: Using Radical Operations In Real Life
Triangle # 1
6 inch (Left)/__\Hypotenuse=x (right side)
9 inch (bottom)
Triangle # 2
7 inch (left) /__\Hypotenuse=x
7 inch(bottom)
1)Using the Pythagorean theorem, find the length of each hypotenuse. Write the
length of each hypotenuse using radicals ( i.e. n√x ). (Show your work).
1)
2)
2) Without converting the hypotenuse lengths to a decimal, find the area of a
rectangle with a length equivalent to Hypotenuse #1 and a width equivalent to
Hypotenuse #2. Express your answer using radicals.
3) Find the ratio of Hypotenuse #1 to Hypotenuse #2. Express your answer using
radicals
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2=6%5E2%2B9%5E2=36%2B81=117--> x=sqrt%28117%29=sqrt%289%2A13%29=sqrt%289%29%2Asqrt%2813%29=3sqrt%2813%29
x%5E2=7%5E2%2B7%5E2=49%2B49=98--> x=sqrt%2898%29=sqrt%2849%2A2%29=sqrt%2849%29%2Asqrt%282%29=7sqrt%282%29
The area of rectangle with sides measuring 3sqrt%2813%29 and 7sqrt%282%29 is
%283sqrt%2813%29%29%2A%287sqrt%282%29%29=3%2A7%2Asqrt%2813%29%2Asqrt%282%29=21sqrt%2826%29
The ratio of the hypotenuse lengths found above is

I multiplied times the factor 1=sqrt%282%29%2Fsqrt%282%29 to rationalize (meaning getting rid of square roots in the denominator).