SOLUTION: please help me solve 5p^2 + 3p- 2=0 by using the quadratic forula

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Question 541830: please help me solve 5p^2 + 3p- 2=0 by using the quadratic forula
Answer by Maths68(1474) About Me  (Show Source):
You can put this solution on YOUR website!
5p%5E2+%2B+3p-+2=0+
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ap%5E2%2Bbp%2Bc=0 (in our case 5p%5E2%2B3p%2B-2+=+0) has the following solutons:

p%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%283%29%5E2-4%2A5%2A-2=49.

Discriminant d=49 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28-3%2B-sqrt%28+49+%29%29%2F2%5Ca.

p%5B1%5D+=+%28-%283%29%2Bsqrt%28+49+%29%29%2F2%5C5+=+0.4
p%5B2%5D+=+%28-%283%29-sqrt%28+49+%29%29%2F2%5C5+=+-1

Quadratic expression 5p%5E2%2B3p%2B-2 can be factored:
5p%5E2%2B3p%2B-2+=+5%28p-0.4%29%2A%28p--1%29
Again, the answer is: 0.4, -1. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+5%2Ax%5E2%2B3%2Ax%2B-2+%29