SOLUTION: Please solve this equation for me: {{{ sqrt( y+2 )=y }}}

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Question 516050: Please solve this equation for me: +sqrt%28+y%2B2+%29=y+
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
+sqrt%28+y%2B2+%29=y+
square both sides
y + 2 = y^2
Arrange as a quadratic equation
0 = y^2 - y - 2
Factors to:
(y-2)(y+1) = 0
two solutions
y = 2
y = -1
:
Check both solutions in the original problem
y=2
+sqrt%28+2%2B2+%29=+2+; this works
y=-1
+sqrt%28-1%2B2+%29=+-1+ this does not work, only y=2 is a solutions