SOLUTION: I have been away from school the past few days because i was sick, and i am really not understanding these questions. i am also not sure if this is the right section to be asking t

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Question 51085: I have been away from school the past few days because i was sick, and i am really not understanding these questions. i am also not sure if this is the right section to be asking this question in, but nothing else seemed to fit
(x^2-64)/(5x) * (10x^2)/(x+8)
1. what i thought to do is factor the denomanator so it would be (x+8)(x-8)/(5x) * (10x^2)/(x+8) then the two x + 8's cancel out....once u have the final answer as (x-8)/(5x) * (10x^2)/1---do u just multiply?? and how do u multiply??
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Well, it looks like you haven't lost your touch.
Your initial step was quite correct. I am assuming that the task is to simplify the given expression.
%28%28x%5E2-64%29%2F%285x%29%29%28%2810x%5E2%29%2F%28x%2B8%29%29 You correctly factored the numerator of the first fraction.
%28%28%28x%2B8%29%28x-8%29%29%2F%285x%29%29%28%2810x%5E2%29%2F%28x%2B8%29%29 and you also correctly cancelled the (x+8)'s
%28%28x-8%29%2F%285x%29%29%28%2810x%5E2%29%2F1%29 At this point, you can cancel 5x's in the denominator and from the 10x%5E2 in the numerator.
%288-x%29%282x%29 Finally, you can multiply these two factors.
16x-2x%5E2