SOLUTION: x^2-8x+7 x^2+3x-10 ________ X __________ x^2+3x-4 x^2-9x+14

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Question 5072: x^2-8x+7 x^2+3x-10
________ X __________
x^2+3x-4 x^2-9x+14
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%5E2-8x%2B7%29%2F+%28x%5E2%2B3x-4%29+%2A++%28x%5E2%2B3x-10%29%2F+%28x%5E2-9x%2B14%29+

The critical step here is to FACTOR, FACTOR, FACTOR, and FACTOR!!
You are NOT allowed to divide out terms such as x%5E2 or numbers that are involved in addition or subtractions. Everything must be in FACTORED form in order to reduce the fractions.

%28x-7%29%28x-1%29%2F+%28x%2B4%29%28x-1%29+%2A++%28x%2B5%29%28x-2%29%2F+%28x-7%29%28x-2%29+

Now you can divide out the factors that are the same. You can divide out ANY factor of ANY numerator with ANY factor of ANY denominator. This is a good place for a "cartoon" by tutor and owner of this website Igor Chudov, but I haven't learned to do that yet. Maybe he will add a cartoon to this solution to show how the factors divide out. Until then, just divide out the factors of (x-7), (x-1), and (x-2). What is left is the (x+5) in the numerator, and the (x+4) in the denominator.

Final answer: +%28x%2B5%29+%2F%28x%2B4%29+

R^2 at SCC