SOLUTION: Says to find the domain????? f(x)= sqrt (x+1)

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Question 484870: Says to find the domain?????
f(x)= sqrt (x+1)
Found 2 solutions by MathLover1, jim_thompson5910:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=+sqrt+%28x%2B1%29

x%2B1 cannot be equal to 0; so, if x%2B1=0...->...x=-1
and domain are all numbers greater than -1
Solved by pluggable solver: Plot a graph of any function AND its DOMAIN

Here's a graph of function sqrt%28x%2B1%29 (sqrt(x+1)).

The domain is shown on the x axis by a green horizontal line.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
You cannot take the square root of a negative number. So the radicand x+1 must be 0 or positive.


In other words, x%2B1%3E=0 which means that x%3E=-1


So the domain is

Note: the above says that the domain is the set of all real numbers that are greater than or equal to -1.


In interval notation, the domain is [)