Question 483851: What's the answer for square root of x^2-y^2?
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! i believe the answer depends on the values of x and y.
if you set z = sqrt(x^2 - y^2), you can square both sides of that equation to get:
z^2 = x^2 - y^2
if you add y^2 to both sides of that equation, then you get:
z^2 + y^2 = x^2 which can be shown as:
x^2 = z^2 + y^2
this looks a lot like the pythagorean formula of c^2 = a^2 + b^2, except:
x = c
z = a
y = b
c is the hypotenuse of a right triangle.
a and b are legs of the right triangle.
this can be translated to:
x is the hypotenuse of a right triangle.
z and y are legs of the right triangle.
is that what you're looking for?
if not, then what i the problem you are trying to solve?
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