SOLUTION: What is the end behavior of f(x) = –x^3 + 2 ?

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Question 481513: What is the end behavior of f(x) = –x^3 + 2 ?
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

f%28x%29=-x%5E3%2B2
-odd-degree polynomials have ends that head off in opposite directions
-if they start "down" (entering the graphing "box" through the "bottom") and go "up" (leaving the graphing "box" through the "top"), they're positive polynomials;
-if they start "up" and go "down", they're negative polynomials
Since the leading coefficient of this odd-degree polynomial is negative, then its end-behavior is going to mimic a negative cubic:
+graph%28+500%2C+500%2C+-6%2C+5%2C+-10%2C+10%2C-x%5E3%2B2%29+