SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function and graph the function f(x)=-2x^2+2x+3

Algebra ->  Radicals -> SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function and graph the function f(x)=-2x^2+2x+3      Log On


   

Question 480891: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function and graph the function
f(x)=-2x^2+2x+3
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

Using the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex

f(x)= -2x^2+2x+3

f(x)=-2[x^2-x]+3

f(x)=-2[(x-.5)^2 - .25] +3

f(x)=-2[(x-.5)^2 +.5 +3

f(x)=-2[(x-.5)^2 + 3.5  V(.5,3.5), Line of symmetry x = .5

  a = -2 < 0, parabola opens downward, vertex a maxixmum Pt F(x) = 3.5