SOLUTION: Solve these radical equations. 2x= sqrt(10x+6) sqrt(x+5)= 2x sqrt(2x-15)= x/4 sqrt(2x-1)= x+8/2

Algebra ->  Radicals -> SOLUTION: Solve these radical equations. 2x= sqrt(10x+6) sqrt(x+5)= 2x sqrt(2x-15)= x/4 sqrt(2x-1)= x+8/2      Log On


   

Question 459718: Solve these radical equations.
2x= sqrt(10x+6)
sqrt(x+5)= 2x
sqrt(2x-15)= x/4
sqrt(2x-1)= x+8/2
Answer by Gogonati(855) About Me  (Show Source):
You can put this solution on YOUR website!
To solve the equation 2x=sqrt%2810x%2B6%29, we squared both sides of equation
%282x%29%5E2=10x%2B6, set the equation equal to zero 4x%5E2-10x-6=0, using the
quadratic formula we find the roots of the equation.
x=%2810%2B-sqrt%2810%5E2-4%2A4%2A%28-6%29%29%29%2F2%2A4=%2810%2B-sqrt%28196%29%29%2F8, and the roots are:
x=%2810%2B14%29%2F8=3, and x=%2810-14%29%2F8=-1%2F2.
After checking the roots we reject the root x=-1/2 because it doesn't satisfy the original equation.
Answer: The solution is x=3.
In the same way you can solve the other equations.