SOLUTION: solve: -x^4+200=102x^2

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Question 45144: solve: -x^4+200=102x^2
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Is the problem really -x%5E4%2B200=102x%5E2

Set this equal to zero with the x^4 term positive by adding x^4 -200 to each side:
0=x^4 +102x^2 -200.

Now, are you sure you copied this problem correctly, because if the signs had been different, it would have factored nicely. If it had been x^4 +200 = 102x^2, then it would have factored. By subtracting 102x^2 from each side you get:
x^4 -102x^2+ 200 = 0
(x^2 - 100)(x^2-2) = 0

From this there will be two possibilities, each of which has two solutions:
x^2 - 100 = 0
x^2 = 100
x= 10 or x = -10

The second possibility is
x^2 - 2 = 0
x^2 = 2
x=+sqrt%282%29 or x=-sqrt%282%29+

If the problem was correctly stated, then the quadratic formula or completing the square method must be applied.

R^2 at SCC