SOLUTION: I am required to solve using the quadratic formula, if there are no real roots, then that can be an answer too. Thank you. 3=7x-4x(2) the two in parentheses is a power.

Algebra ->  Radicals -> SOLUTION: I am required to solve using the quadratic formula, if there are no real roots, then that can be an answer too. Thank you. 3=7x-4x(2) the two in parentheses is a power.      Log On


   

Question 44929: I am required to solve using the quadratic formula, if there are no real roots, then that can be an answer too. Thank you.
3=7x-4x(2) the two in parentheses is a power.
Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
I am required to solve using the quadratic formula, if there are no real roots, then that can be an answer too. Thank you.
3=7x-4x(2) the two in parentheses is a power.
4X^2-7X+3=0...IF AX^2+BX+C=0...THEN
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
A=4...B=-7...C=3
x+=+%287+%2B-+sqrt%28+%28-7%29%5E2-4%2A4%2A3+%29%29%2F%282%2A4%29+
x=%287%2B-sqrt%2849-48%29%29%2F8
x=(7+1)/6=8/8=1.....and
x=(7-1)/8=6/8=3/4