SOLUTION: how do you solve {{{-12/sqrt(18x)}}}? I have gotten to {{{-12sqrt( 2*9*x )/(18x)}}} but am unsure of what to do with the numbers under the radicand

Algebra ->  Radicals -> SOLUTION: how do you solve {{{-12/sqrt(18x)}}}? I have gotten to {{{-12sqrt( 2*9*x )/(18x)}}} but am unsure of what to do with the numbers under the radicand      Log On


   



Question 449279: how do you solve -12%2Fsqrt%2818x%29? I have gotten to -12sqrt%28+2%2A9%2Ax+%29%2F%2818x%29 but am unsure of what to do with the numbers under the radicand
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
-12%2Fsqrt%2818x%29
Don't start out multiplying by the entire denominator over itself.
Instead, first get the prime factorization of 18 as 2*3²

-12%2Fsqrt%282%2A3%5E2%2Ax%29

To get a perfect square under the radical,
we need to multiply what's under there by another 2 and also
by another x, so we multiply by sqrt%282x%29%2Fsqrt%282x%29 which is just 1 in value.

%28-12%2Fsqrt%282%2A3%5E2%2Ax%29%29%28sqrt%282x%29%2Fsqrt%282x%29%29

Multiplying under the radicals in the denominator:

%28-12sqrt%282x%29%29%2Fsqrt%282%5E2%2A3%5E2%2Ax%5E2%29

Now we will no longer have a radical in the
denominator because we can take the square roots
of all those squares

%28-12sqrt%282x%29%29%2F%282%2A3%2Ax%29

%28-12sqrt%282x%29%29%2F%286x%29

Then the 6 divides into the 12 and we have:

%28-2sqrt%282x%29%29%2Fx

Edwin