SOLUTION: Please help me solve this equation: {{{ x^2= sqrt(x+20) }}}

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Question 448756: Please help me solve this equation: +x%5E2=+sqrt%28x%2B20%29+
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
+x%5E2=+sqrt%28x%2B20%29+
square both sides
+%28x%5E2%29%5E2+=+%28sqrt%28x%2B20%29%29%5E2+
x%5E4+=+x+%2B+20
x%5E4+-+x+-+20 = 0
:
Solve this equation on a graphing calc
+graph%28+300%2C+200%2C+-4%2C+4%2C+-25%2C+10%2C+x%5E4-x-20%29+
Two solutions
x=+2.17
x=-2.058
:
You can check both solutions in the original problem