SOLUTION: Graph the function f(x)= -2x^2 + 4x + 1

 

Hi

Graph the function

Note: vertex form of a parabola,  where(h,k) is the vertex

f(x)= -2x^2 + 4x + 1  |y-intercept is (0,1)

f(x)= -2[(x-1)^2 -1] + 1

f(x)= -2(x-1)^2 +2 + 1

f(x)= -2(x-1)^2 + 3 | V(1,3), Parabola opens downward a = -2 < 0

x-intercepts: x = 1 ± sqrt(3/2) x = 1 ± 1.2247









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