SOLUTION: Find the value of the discriminant for 9x^2+1=6x. Then describe the number and type of roots for the equation. Thanks

Algebra ->  Radicals -> SOLUTION: Find the value of the discriminant for 9x^2+1=6x. Then describe the number and type of roots for the equation. Thanks      Log On


   

Question 43485: Find the value of the discriminant for 9x^2+1=6x. Then describe the number and type of roots for the equation.
Thanks
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
9x%5E2+%2B+1+=+6x
9x%5E2+-+6x+%2B+1+=+0
Disciminant: b%5E2+-+4ac where the from: ax%5E2+%2B+bx+%2B+c+=+0
a=9 b=-6 c=1
b%5E2+-+4ac
%28-6%29%5E2+-+4%289%29%281%29
36+-+36
0
Since the discriminant is zero, there is only one real root.
+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+9x%5E2+-+6x+%2B+1%29+