SOLUTION: h=-16t^2+96t+112

 

Hi, 

You did not state the exact nature of your Question:

h=-16t^2+96t+112   |Represents a parabola opening downward

h= -16(t-3)^2 + 144 + 160 |completing Square to find Vertex

the vertex form of a parabola,  where(h,k) is the vertex

 Vertex(3,304)  h reaches a maximum of 304 when t = 3