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|Squaring both sides of the Equation
x-2 = x^2 - 8x + 16
x^2 -9x + 18 = 0
factoring
(x-3)(x-6) = 0 Note:SUM of the outside terms(-6x) and the inside terms(-3x) = -9x
(x-3)= 0 x = 3 |Tossing out: sqrt(1) ≠ -1
(x-6) = 0 x = 6
It is always recommended to 'check out' the solutions found in the original EQ