SOLUTION: How many real roots and or imaginary roots does the following equation have: x^2 - 625 = 0 Thanks
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Algebra: Radicals -- complicated equations involving roots
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Question 42547
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How many real roots and or imaginary roots does the following equation have:
x^2 - 625 = 0
Thanks
Answer by
checkley71(8403)
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x~2-625=0 or (x+25)(x-25)=0 or x=-25 & x=+25