SOLUTION: 2(x-7)^1/3 +5 = 7 (What would I need to do here?) Also.. 2x^1/2 +8 = 0

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Question 407493: 2(x-7)^1/3 +5 = 7
(What would I need to do here?)
Also..
2x^1/2 +8 = 0

Found 2 solutions by jim_thompson5910, graphmatics:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
# 1

2%28x-7%29%5E%281%2F3%29%5E%22%22+%2B5+=+7


2%28x-7%29%5E%281%2F3%29%5E%22%22+=+7-5


2%28x-7%29%5E%281%2F3%29%5E%22%22+=+2


%28x-7%29%5E%281%2F3%29%5E%22%22+=+2%2F2


%28x-7%29%5E%281%2F3%29%5E%22%22+=+1


root%283%2Cx-7%29+=+1


x-7+=+1%5E3


x-7+=+1


x+=+1%2B7


x+=+8


So the solution is x+=+8

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# 2

2x%5E%281%2F2%29%5E%22%22++%2B8+=+0+


2x%5E%281%2F2%29%5E%22%22++=+-8+


x%5E%281%2F2%29%5E%22%22++=+-4+


sqrt%28x%29+=+-4+


Recall that the range of the square root function is nonnegative. So the last equation is NOT possible. So there are NO solutions to the last equation.


Because the set of equations above are all equivalent, this means that there are NO solutions to the equation 2x%5E%281%2F2%29+%2B8+=+0+


If you need more help, email me at jim_thompson5910@hotmail.com

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Jim

Answer by graphmatics(170) About Me  (Show Source):
You can put this solution on YOUR website!
To move the 5 from the left side of the equation to the right side of the equation add -5 to both sides of the equation
2(x-7)^1/3 + 5 + -5 = 7-5
2(x-7)^1/3 = 2
(x-7)^1/3 = 1
now we simply raise each side of the equation to the power 3 and get
((x-7)^1/3)^3 = 1^3
x-7 = 1
x = 1+7
x=8

to solve 2x^1/2 + 8 = 0 is similar.