SOLUTION: Find (if it exists) each function value of f(t)=the square root of t^2+1 and so f(0)=?

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Question 401218: Find (if it exists) each function value of f(t)=the square root of t^2+1 and so f(0)=?
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
I'm unsure if you mean f%28t%29+=+sqrt%28t%5E2%29+%2B+1 or f%28t%29+=+sqrt%28t%5E2+%2B+1%29. In either case you get f%280%29+=+1, since you replace t with 0.