SOLUTION: Please help, I am soooo lost with 2 problems: 1: Cube Root of 270x divided by cube root of 10xy^2 2: Cube root of x^2 divided by cube root of 4 Thank you so much!

Algebra ->  Radicals -> SOLUTION: Please help, I am soooo lost with 2 problems: 1: Cube Root of 270x divided by cube root of 10xy^2 2: Cube root of x^2 divided by cube root of 4 Thank you so much!      Log On


   



Question 398823: Please help, I am soooo lost with 2 problems:
1: Cube Root of 270x divided by cube root of 10xy^2
2: Cube root of x^2 divided by cube root of 4
Thank you so much!

Found 2 solutions by josmiceli, jsmallt9:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!

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Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
With expressions like these, a radical over the same kind of radical, I like to use the following procedure:
  1. Use the property root%28a%2C+p%29%2Froot%28a%2C+q%29+=+root%28a%2C+p%2Fq%29 to combine the two radicals into a single radical.
  2. Reduce the fraction inside the radical, if possible.
  3. If the denominator is not a perfect power of the type of radical, then multiply the numerator and denominator by some expression so that the denominator becomes a perfect power of the type of radical.
  4. Use the same property as step 1, only in reverse, to split the radical back to a radical over a radical.
  5. Simplify. If the previous steps were done correctly, there should be no radicals remaining in the denominator.

Let's see this in action.
root%283%2C+170x%29%2Froot%283%2C+10xy%5E2%29
1) Combine radicals:
root%283%2C+170x%2F10xy%5E2%29
2) Reduce the fraction inside. The x's cancel and a factor of 10 cancels leaving:
root%283%2C+17%2Fy%5E2%29
3) If the denominator is is not a perfect power of the type of radcial, then multiply the numerator and denominator by whatever makes the denominator a perfect power of the type of radical. Since we are working with cube roots, we are looking to make the denominator a perfect cube. All we need is another factor of y:
root%283%2C+%2817%2Fy%5E2%29%28y%2Fy%29%29
which simplifies to:
root%283%2C+17y%2Fy%5E3%29
4) Split the radical:
root%283%2C+17y%29%2Froot%283%2C+y%5E3%29
5. Simplify.
root%283%2C+17y%29%2Fy
Since there are no perfect cube factors in 17y, the radical in the numerator will not simplify further.

root%283%2C+x%5E2%29%2Froot%283+4%29
1. Combine the radicals:
root%283%2C+x%5E2%2F4%29
2. Reduce the fraction. This fraction will not reduce.
3. Make the denominator a power of the type of radical. The "nearest" perfect cube to 4 is 8. So we just have to multiply the numerator and denominator by 2:
root%283%2C+%28x%5E2%2F4%29%282%2F2%29%29
which simplifies to:
root%283%2C+2x%5E2%2F8%29
4. Split the radical:
root%283%2C+2x%5E2%29%2Froot%283%2C+8%29
5. Simplify.
root%283%2C+2x%5E2%29%2F2
There are no perfect cube factors in 2x%5E2 so the numerator will no simplify any further.

Note 1: The procedure I've described is not the only way to simplify your expressions. But it is pretty efficient at handing radical over radical expression.
Note 2: Any procedure used correctly should simplify your expressions to the same results as we got above.
Note 3: If the radicals are of different types then use fractional exponents to make them the same type. For example:
sqrt%282x%29%2Froot%283%2C+y%5E2%29
%282x%29%5E%281%2F2%29%2F%28y%5E2%29%5E%281%2F3%29
%282x%29%5E%283%2F6%29%2F%28y%5E2%29%5E%282%2F6%29
%28%282x%29%5E3%29%5E%281%2F6%29%2F%28%28y%5E2%29%5E2%29%5E%281%2F6%29
root%286%2C+%282x%29%5E3%29%2Froot%286%2C+%28y%5E2%29%5E2%29
root%286%2C+8x%5E3%29%2Froot%286%2C+y%5E4%29
Now that the radicals are both 6th roots, we can use the procedure above:
1. Combine:
root%286%2C+8x%5E3%2Fy%5E4%29
2. Reduce. This will not reduce.
3. Make the denominator a power of the type of radical:
root%286%2C+%288x%5E3%2Fy%5E4%29%28y%5E2%2Fy%5E2%29%29
root%286%2C+%288x%5E3y%5E2%29%2Fy%5E6%29
4. Split
root%286%2C+8x%5E3y%5E2%29%2Froot%286%2C+y%5E6%29
5. Simplify. Since sixth roots are supposed to be positive and since we do not know if y is positive, we should use absolute value when simplifying root%286%2C+y%5E6%29:
root%286%2C+8x%5E3y%5E2%29%2Fabs%28y%29